Distance from Jefferson City to Klamath Falls
Distance from Jefferson City to Klamath Falls is 2,533 kilometers. This air travel distance is equal to 1,574 miles.
The air travel (bird fly) shortest distance between Jefferson City and Klamath Falls is 2,533 km or 1,574 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Klamath Falls, It takes 2.81 hours to arrive.
Jefferson City
Jefferson City is located in United States.
GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
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Latitude | 38.57670 |
Longitude | -92.17352 |
Altitude | 195 m |
Country | United States |
Jefferson City Distances to Cities
Jefferson City | Distance |
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Distance from Jefferson City to Sacramento | 2,544 km |
Distance from Jefferson City to Boston | 1,834 km |
Distance from Jefferson City to San Francisco | 2,640 km |
Distance from Jefferson City to Los Angeles | 2,386 km |
Distance from Jefferson City to Dallas | 767 km |
Klamath Falls
Klamath Falls is located in United States.
GPS Coordinates | 42° 13´ 29.5320'' N 121° 46´ 54.0120'' W |
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Latitude | 42.22487 |
Longitude | -121.78167 |
Altitude | 1254 m |
Country | United States |
Klamath Falls Distances to Cities
Klamath Falls | Distance |
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Distance from Klamath Falls to Woodburn | 336 km |
Distance from Klamath Falls to Mcminnville | 351 km |
Distance from Klamath Falls to Oregon City | 354 km |
Distance from Klamath Falls to Lake Oswego | 362 km |
Distance from Klamath Falls to Olympia | 542 km |