Distance from Jefferson City to Johnston
Distance from Jefferson City to Johnston is 368 kilometers. This air travel distance is equal to 229 miles.
The air travel (bird fly) shortest distance between Jefferson City and Johnston is 368 km= 229 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Johnston, It takes 0.41 hours to arrive.
Jefferson City
Jefferson City is located in United States.
GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
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Latitude | 38.57670 |
Longitude | -92.17352 |
Altitude | 195 m |
Country | United States |
Jefferson City Distances to Cities
Jefferson City | Distance |
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Distance from Jefferson City to Sacramento | 2,544 km |
Distance from Jefferson City to Boston | 1,834 km |
Distance from Jefferson City to San Francisco | 2,640 km |
Distance from Jefferson City to Los Angeles | 2,386 km |
Distance from Jefferson City to Dallas | 767 km |
Johnston
Johnston is located in United States.
GPS Coordinates | 41° 40´ 22.9440'' N 93° 41´ 51.7920'' W |
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Latitude | 41.67304 |
Longitude | -93.69772 |
Altitude | 251 m |
Country | United States |
Johnston Distances to Cities
Johnston | Distance |
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Distance from Johnston to Southbridge | 1,794 km |
Distance from Johnston to Hopkins | 362 km |
Distance from Johnston to West Warwick | 1,841 km |
Distance from Johnston to Lennox | 2,325 km |
Distance from Johnston to Minot | 943 km |