Distance from Jefferson City to Holyoke
Distance from Jefferson City to Holyoke is 1,705 kilometers. This air travel distance is equal to 1,059 miles.
The air travel (bird fly) shortest distance between Jefferson City and Holyoke is 1,705 km or 1,059 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Holyoke, It takes 1.89 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Holyoke
Holyoke is located in United States.
| GPS Coordinates | 42° 12´ 15.3360'' N 72° 36´ 58.3200'' W |
|---|---|
| Latitude | 42.20426 |
| Longitude | -72.61620 |
| Altitude | 61 m |
| Country | United States |
Holyoke Distances to Cities
| Holyoke | Distance |
|---|---|
| Distance from Holyoke to Stoneham | 129 km |
| Distance from Holyoke to Manchester Nh | 130 km |
| Distance from Holyoke to Chandler | 3,560 km |
| Distance from Holyoke to Leominster | 79 km |
| Distance from Holyoke to Castlewood | 2,720 km |