Distance from Jefferson City to Cleveland Heights
Distance from Jefferson City to Cleveland Heights is 962 kilometers. This air travel distance is equal to 598 miles.
The air travel (bird fly) shortest distance between Jefferson City and Cleveland Heights is 962 km or 598 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Cleveland Heights, It takes 1.07 hours to arrive.
Jefferson City
Jefferson City is located in United States.
GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
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Latitude | 38.57670 |
Longitude | -92.17352 |
Altitude | 195 m |
Country | United States |
Jefferson City Distances to Cities
Jefferson City | Distance |
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Distance from Jefferson City to Sacramento | 2,544 km |
Distance from Jefferson City to Boston | 1,834 km |
Distance from Jefferson City to San Francisco | 2,640 km |
Distance from Jefferson City to Los Angeles | 2,386 km |
Distance from Jefferson City to Dallas | 767 km |
Cleveland Heights
Cleveland Heights is located in United States.
GPS Coordinates | 41° 31´ 12.1800'' N 81° 33´ 22.4640'' W |
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Latitude | 41.52005 |
Longitude | -81.55624 |
Altitude | 288 m |
Country | United States |
Cleveland Heights Distances to Cities
Cleveland Heights | Distance |
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Distance from Cleveland Heights to Lemont | 538 km |
Distance from Cleveland Heights to Libertyville | 537 km |
Distance from Cleveland Heights to Avon | 41 km |
Distance from Cleveland Heights to Elmhurst | 533 km |
Distance from Cleveland Heights to Redford | 173 km |