Distance from Jefferson City to Arvin
Distance from Jefferson City to Arvin is 2,396 kilometers. This air travel distance is equal to 1,489 miles.
The air travel (bird fly) shortest distance between Jefferson City and Arvin is 2,396 km= 1,489 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Arvin, It takes 2.66 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Arvin
Arvin is located in United States.
| GPS Coordinates | 35° 12´ 32.8680'' N 118° 49´ 42.3480'' W |
|---|---|
| Latitude | 35.20913 |
| Longitude | -118.82843 |
| Altitude | 137 m |
| Country | United States |
Arvin Distances to Cities
| Arvin | Distance |
|---|---|
| Distance from Arvin to Coachella | 297 km |
| Distance from Arvin to Oildale | 29 km |
| Distance from Arvin to Lomita | 164 km |
| Distance from Arvin to Laguna Beach | 208 km |
| Distance from Arvin to Lamont | 10 km |