Distance from Jefferson City to Amsterdam
Distance from Jefferson City to Amsterdam is 1,590 kilometers. This air travel distance is equal to 988 miles.
The air travel (bird fly) shortest distance between Jefferson City and Amsterdam is 1,590 km or 988 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Amsterdam, It takes 1.76 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Amsterdam
Amsterdam is located in United States.
| GPS Coordinates | 42° 56´ 19.2840'' N 74° 11´ 17.4840'' W |
|---|---|
| Latitude | 42.93869 |
| Longitude | -74.18819 |
| Altitude | 110 m |
| Country | United States |
Amsterdam Distances to Cities
| Amsterdam | Distance |
|---|---|
| Distance from Amsterdam to New York City | 248 km |
| Distance from Amsterdam to Limerick | 321 km |
| Distance from Amsterdam to Sunnyvale | 4,068 km |
| Distance from Amsterdam to Bothell | 3,739 km |
| Distance from Amsterdam to Antioch | 4,021 km |