Distance from Jefferson City to Altus
Distance from Jefferson City to Altus is 775 kilometers. This air travel distance is equal to 482 miles.
The air travel (bird fly) shortest distance between Jefferson City and Altus is 775 km or 482 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Altus, It takes 0.86 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Altus
Altus is located in United States.
| GPS Coordinates | 34° 38´ 17.2680'' N 99° 20´ 2.3280'' W |
|---|---|
| Latitude | 34.63813 |
| Longitude | -99.33398 |
| Altitude | 430 m |
| Country | United States |
Altus Distances to Cities
| Altus | Distance |
|---|---|
| Distance from Altus to Lubbock | 261 km |
| Distance from Altus to Frisco | 285 km |
| Distance from Altus to Santa Fe | 613 km |
| Distance from Altus to Mcalester | 328 km |
| Distance from Altus to Houston | 657 km |