Distance from Jacksonville to Providence
Distance from Jacksonville to Providence is 1,602 kilometers. This air travel distance is equal to 995 miles.
The air travel (bird fly) shortest distance between Jacksonville and Providence is 1,602 km or 995 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jacksonville to Providence, It takes 1.78 hours to arrive.
Jacksonville
Jacksonville is located in United States.
| GPS Coordinates (DMS) | 39° 44´ 2.1840'' N 90° 13´ 44.4360'' W |
|---|---|
| Latitude | 39.73394 |
| Longitude | -90.22901 |
| Altitude | 190 m |
| Country | United States |
Jacksonville Distances to Cities
Providence
Providence is located in United States.
| GPS Coordinates | 41° 49´ 26.3640'' N 71° 24´ 46.1880'' W |
|---|---|
| Latitude | 41.82399 |
| Longitude | -71.41283 |
| Altitude | -17 m |
| Country | United States |
Providence Distances to Cities
| Providence | Distance |
|---|---|
| Distance from Providence to Boston | 66 km |
| Distance from Providence to Smithfield | 16 km |
| Distance from Providence to Phoenix | 3,671 km |
| Distance from Providence to Virginia | 790 km |
| Distance from Providence to Palmdale | 4,117 km |