Distance from Jacksonville to Albany
Distance from Jacksonville to Albany is 1,538 kilometers. This air travel distance is equal to 956 miles.
The air travel (bird fly) shortest distance between Jacksonville and Albany is 1,538 km= 956 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jacksonville to Albany, It takes 1.71 hours to arrive.
Jacksonville
Jacksonville is located in United States.
| GPS Coordinates (DMS) | 30° 19´ 55.8480'' N 81° 39´ 20.3400'' W |
|---|---|
| Latitude | 30.33218 |
| Longitude | -81.65565 |
| Altitude | 12 m |
| Country | United States |
Jacksonville Distances to Cities
Albany
Albany is located in United States.
| GPS Coordinates | 42° 39´ 9.2880'' N 73° 45´ 22.4280'' W |
|---|---|
| Latitude | 42.65258 |
| Longitude | -73.75623 |
| Altitude | 50 m |
| Country | United States |
Albany Distances to Cities
| Albany | Distance |
|---|---|
| Distance from Albany Ny to Las Vegas | 3,598 km |
| Distance from Albany Ny to Kingston | 83 km |
| Distance from Albany Ny to Sacramento | 4,011 km |
| Distance from Albany Ny to San Francisco | 4,120 km |
| Distance from Albany Ny to Los Angeles | 3,956 km |