Distance from Jacksonville Beach to Albany
Distance from Jacksonville Beach to Albany is 1,531 kilometers. This air travel distance is equal to 951 miles.
The air travel (bird fly) shortest distance between Jacksonville Beach and Albany is 1,531 km or 951 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jacksonville Beach to Albany, It takes 1.7 hours to arrive.
Jacksonville Beach
Jacksonville Beach is located in United States.
| GPS Coordinates (DMS) | 30° 17´ 40.8840'' N 81° 23´ 35.3040'' W |
|---|---|
| Latitude | 30.29469 |
| Longitude | -81.39314 |
| Altitude | 3 m |
| Country | United States |
Jacksonville Beach Distances to Cities
Albany
Albany is located in United States.
| GPS Coordinates | 42° 39´ 9.2880'' N 73° 45´ 22.4280'' W |
|---|---|
| Latitude | 42.65258 |
| Longitude | -73.75623 |
| Altitude | 50 m |
| Country | United States |
Albany Distances to Cities
| Albany | Distance |
|---|---|
| Distance from Albany Ny to Las Vegas | 3,598 km |
| Distance from Albany Ny to Kingston | 83 km |
| Distance from Albany Ny to Sacramento | 4,011 km |
| Distance from Albany Ny to San Francisco | 4,120 km |
| Distance from Albany Ny to Los Angeles | 3,956 km |