Distance from Guadalupe Victoria to Oakland Park
Distance from Guadalupe Victoria to Oakland Park is 3,451 kilometers. This air travel distance is equal to 2,144 miles.
The air travel (bird fly) shortest distance between Guadalupe Victoria and Oakland Park is 3,451 km= 2,144 miles.
If you travel with an airplane (which has average speed of 560 miles) from Guadalupe Victoria to Oakland Park, It takes 3.83 hours to arrive.
Guadalupe Victoria
Guadalupe Victoria is located in Mexico.
| GPS Coordinates (DMS) | 32° 17´ 21.2640'' N 115° 6´ 19.2240'' W |
|---|---|
| Latitude | 32.28924 |
| Longitude | -115.10534 |
| Altitude | 13 m |
| Country | Mexico |
Guadalupe Victoria Distances to Cities
| Guadalupe Victoria | Distance |
|---|---|
| Distance from Guadalupe Victoria to Mcallen | 1,771 km |
| Distance from Guadalupe Victoria to Toledo | 2,975 km |
| Distance from Guadalupe Victoria to San Benito | 1,828 km |
| Distance from Guadalupe Victoria to Laredo | 1,595 km |
| Distance from Guadalupe Victoria to Donna | 1,789 km |
Oakland Park
Oakland Park is located in United States.
| GPS Coordinates | 26° 10´ 20.3160'' N 80° 7´ 55.1640'' W |
|---|---|
| Latitude | 26.17231 |
| Longitude | -80.13199 |
| Altitude | 6 m |
| Country | United States |