Distance from Florida to Seymour
Distance from Florida to Seymour is 1,317 kilometers. This air travel distance is equal to 818 miles.
The air travel (bird fly) shortest distance between Florida and Seymour is 1,317 km= 818 miles.
If you travel with an airplane (which has average speed of 560 miles) from Florida to Seymour, It takes 1.46 hours to arrive.
Florida
Florida is located in United States.
| GPS Coordinates (DMS) | 27° 39´ 53.3880'' N 81° 30´ 56.7000'' W |
|---|---|
| Latitude | 27.66483 |
| Longitude | -81.51575 |
| Altitude | 29 m |
| Country | United States |
Florida Distances to Cities
| Florida | Distance |
|---|---|
| Distance from Florida to California | 3,687 km |
| Distance from Florida to New York | 1,603 km |
| Distance from Florida to Texas | 1,838 km |
| Distance from Florida to Georgia | 516 km |
| Distance from Florida to New Jersey | 1,523 km |
Seymour
Seymour is located in United States.
| GPS Coordinates | 38° 57´ 33.1920'' N 85° 53´ 24.9000'' W |
|---|---|
| Latitude | 38.95922 |
| Longitude | -85.89025 |
| Altitude | 185 m |
| Country | United States |
Seymour Distances to Cities
| Seymour | Distance |
|---|---|
| Distance from Seymour In to New York City | 1,035 km |
| Distance from Seymour In to Mansfield Ma | 1,288 km |
| Distance from Seymour In to Fairland | 773 km |
| Distance from Seymour In to Waverly | 433 km |
| Distance from Seymour In to Farmington Mn | 872 km |