Distance from Florida to Seymour
Distance from Florida to Seymour is 1,707 kilometers. This air travel distance is equal to 1,061 miles.
The air travel (bird fly) shortest distance between Florida and Seymour is 1,707 km= 1,061 miles.
If you travel with an airplane (which has average speed of 560 miles) from Florida to Seymour, It takes 1.89 hours to arrive.
Florida
Florida is located in United States.
GPS Coordinates (DMS) | 27° 39´ 53.3880'' N 81° 30´ 56.7000'' W |
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Latitude | 27.66483 |
Longitude | -81.51575 |
Altitude | 29 m |
Country | United States |
Florida Distances to Cities
Florida | Distance |
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Distance from Florida to California | 3,687 km |
Distance from Florida to New York | 1,603 km |
Distance from Florida to Texas | 1,838 km |
Distance from Florida to Georgia | 516 km |
Distance from Florida to New Jersey | 1,523 km |
Seymour
Seymour is located in United States.
GPS Coordinates | 41° 23´ 48.3360'' N 73° 4´ 33.3840'' W |
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Latitude | 41.39676 |
Longitude | -73.07594 |
Altitude | 30 m |
Country | United States |
Seymour Distances to Cities
Seymour | Distance |
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Distance from Seymour Ct to Torrance | 4,036 km |
Distance from Seymour Ct to Orange Ca | 3,998 km |
Distance from Seymour Ct to Cambridge | 196 km |
Distance from Seymour Ct to Albany Ca | 4,186 km |
Distance from Seymour Ct to Bedford Nh | 215 km |