Distance from Florida to Sayreville Junction
Distance from Florida to Sayreville Junction is 1,566 kilometers. This air travel distance is equal to 973 miles.
The air travel (bird fly) shortest distance between Florida and Sayreville Junction is 1,566 km or 973 miles.
If you travel with an airplane (which has average speed of 560 miles) from Florida to Sayreville Junction, It takes 1.74 hours to arrive.
Florida
Florida is located in United States.
| GPS Coordinates (DMS) | 27° 39´ 53.3880'' N 81° 30´ 56.7000'' W |
|---|---|
| Latitude | 27.66483 |
| Longitude | -81.51575 |
| Altitude | 29 m |
| Country | United States |
Florida Distances to Cities
| Florida | Distance |
|---|---|
| Distance from Florida to California | 3,687 km |
| Distance from Florida to New York | 1,603 km |
| Distance from Florida to Texas | 1,838 km |
| Distance from Florida to Georgia | 516 km |
| Distance from Florida to New Jersey | 1,523 km |
Sayreville Junction
Sayreville Junction is located in United States.
| GPS Coordinates | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
|---|---|
| Latitude | 40.46538 |
| Longitude | -74.33043 |
| Altitude | 35 m |
| Country | United States |