Distance from Florida to Savage
Distance from Florida to Savage is 2,171 kilometers. This air travel distance is equal to 1,349 miles.
The air travel (bird fly) shortest distance between Florida and Savage is 2,171 km or 1,349 miles.
If you travel with an airplane (which has average speed of 560 miles) from Florida to Savage, It takes 2.41 hours to arrive.
Florida
Florida is located in United States.
GPS Coordinates (DMS) | 27° 39´ 53.3880'' N 81° 30´ 56.7000'' W |
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Latitude | 27.66483 |
Longitude | -81.51575 |
Altitude | 29 m |
Country | United States |
Florida Distances to Cities
Florida | Distance |
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Distance from Florida to California | 3,687 km |
Distance from Florida to New York | 1,603 km |
Distance from Florida to Texas | 1,838 km |
Distance from Florida to Georgia | 516 km |
Distance from Florida to New Jersey | 1,523 km |
Savage
Savage is located in United States.
GPS Coordinates | 44° 46´ 44.8680'' N 93° 20´ 10.8240'' W |
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Latitude | 44.77913 |
Longitude | -93.33634 |
Altitude | 216 m |
Country | United States |
Savage Distances to Cities
Savage | Distance |
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Distance from Savage to Rye | 1,656 km |
Distance from Savage to Lyndhurst | 1,628 km |
Distance from Savage to Summit | 1,613 km |
Distance from Savage to Wooster | 1,031 km |
Distance from Savage to Colonia | 1,624 km |