Distance from Florida to San Angelo
Distance from Florida to San Angelo is 1,879 kilometers. This air travel distance is equal to 1,168 miles.
The air travel (bird fly) shortest distance between Florida and San Angelo is 1,879 km= 1,168 miles.
If you travel with an airplane (which has average speed of 560 miles) from Florida to San Angelo, It takes 2.08 hours to arrive.
Florida
Florida is located in United States.
| GPS Coordinates (DMS) | 27° 39´ 53.3880'' N 81° 30´ 56.7000'' W |
|---|---|
| Latitude | 27.66483 |
| Longitude | -81.51575 |
| Altitude | 29 m |
| Country | United States |
Florida Distances to Cities
| Florida | Distance |
|---|---|
| Distance from Florida to California | 3,687 km |
| Distance from Florida to New York | 1,603 km |
| Distance from Florida to Texas | 1,838 km |
| Distance from Florida to Georgia | 516 km |
| Distance from Florida to New Jersey | 1,523 km |
San Angelo
San Angelo is located in United States.
| GPS Coordinates | 31° 27´ 49.5720'' N 100° 26´ 13.3440'' W |
|---|---|
| Latitude | 31.46377 |
| Longitude | -100.43704 |
| Altitude | 564 m |
| Country | United States |
San Angelo Distances to Cities
| San Angelo | Distance |
|---|---|
| Distance from San Angelo to Eagle | 1,948 km |
| Distance from San Angelo to West Odessa | 200 km |
| Distance from San Angelo to Moscow | 2,210 km |
| Distance from San Angelo to Twin Falls | 1,749 km |
| Distance from San Angelo to Albany Or | 2,455 km |