Distance from Florida Ridge to Jefferson City
Distance from Florida Ridge to Jefferson City is 1,640 kilometers. This air travel distance is equal to 1,019 miles.
The air travel (bird fly) shortest distance between Florida Ridge and Jefferson City is 1,640 km or 1,019 miles.
If you travel with an airplane (which has average speed of 560 miles) from Florida Ridge to Jefferson City, It takes 1.82 hours to arrive.
Florida Ridge
Florida Ridge is located in United States.
| GPS Coordinates (DMS) | 27° 34´ 49.1160'' N 80° 23´ 12.1920'' W |
|---|---|
| Latitude | 27.58031 |
| Longitude | -80.38672 |
| Altitude | 8 m |
| Country | United States |
Florida Ridge Distances to Cities
| Florida Ridge | Distance |
|---|---|
| Distance from Florida Ridge to Miami | 201 km |
| Distance from Florida Ridge to Ashburn | 1,300 km |
| Distance from Florida Ridge to Fort Myers | 179 km |
| Distance from Florida Ridge to Placentia | 3,637 km |
| Distance from Florida Ridge to Plant City | 177 km |
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |