Distance from Faribault to Sacramento
Distance from Faribault to Sacramento is 2,429 kilometers. This air travel distance is equal to 1,509 miles.
The air travel (bird fly) shortest distance between Faribault and Sacramento is 2,429 km or 1,509 miles.
If you travel with an airplane (which has average speed of 560 miles) from Faribault to Sacramento, It takes 2.7 hours to arrive.
Faribault
Faribault is located in United States.
| GPS Coordinates (DMS) | 44° 17´ 41.8560'' N 93° 16´ 7.7880'' W |
|---|---|
| Latitude | 44.29496 |
| Longitude | -93.26883 |
| Altitude | 304 m |
| Country | United States |
Faribault Distances to Cities
Sacramento
Sacramento is located in United States.
| GPS Coordinates | 38° 34´ 53.6520'' N 121° 29´ 39.8400'' W |
|---|---|
| Latitude | 38.58157 |
| Longitude | -121.49440 |
| Altitude | 14 m |
| Country | United States |