Distance from Faribault to Providence
Distance from Faribault to Providence is 1,796 kilometers. This air travel distance is equal to 1,116 miles.
The air travel (bird fly) shortest distance between Faribault and Providence is 1,796 km or 1,116 miles.
If you travel with an airplane (which has average speed of 560 miles) from Faribault to Providence, It takes 1.99 hours to arrive.
Faribault
Faribault is located in United States.
| GPS Coordinates (DMS) | 44° 17´ 41.8560'' N 93° 16´ 7.7880'' W |
|---|---|
| Latitude | 44.29496 |
| Longitude | -93.26883 |
| Altitude | 304 m |
| Country | United States |
Faribault Distances to Cities
Providence
Providence is located in United States.
| GPS Coordinates | 41° 49´ 26.3640'' N 71° 24´ 46.1880'' W |
|---|---|
| Latitude | 41.82399 |
| Longitude | -71.41283 |
| Altitude | -17 m |
| Country | United States |
Providence Distances to Cities
| Providence | Distance |
|---|---|
| Distance from Providence to Boston | 66 km |
| Distance from Providence to Smithfield | 16 km |
| Distance from Providence to Phoenix | 3,671 km |
| Distance from Providence to Virginia | 790 km |
| Distance from Providence to Palmdale | 4,117 km |