Distance from Columbus to Sayreville Junction
Distance from Columbus to Sayreville Junction is 740 kilometers. This air travel distance is equal to 460 miles.
The air travel (bird fly) shortest distance between Columbus and Sayreville Junction is 740 km= 460 miles.
If you travel with an airplane (which has average speed of 560 miles) from Columbus to Sayreville Junction, It takes 0.82 hours to arrive.
Columbus
Columbus is located in United States.
| GPS Coordinates (DMS) | 39° 57´ 40.2480'' N 82° 59´ 55.6440'' W |
|---|---|
| Latitude | 39.96118 |
| Longitude | -82.99879 |
| Altitude | 242 m |
| Country | United States |
Columbus Distances to Cities
| Columbus | Distance |
|---|---|
| Distance from Columbus Oh to San Francisco | 3,402 km |
| Distance from Columbus Oh to Sacramento | 3,300 km |
| Distance from Columbus Oh to Los Angeles | 3,183 km |
| Distance from Columbus Oh to Las Vegas | 2,836 km |
| Distance from Columbus Oh to Denver | 1,877 km |
Sayreville Junction
Sayreville Junction is located in United States.
| GPS Coordinates | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
|---|---|
| Latitude | 40.46538 |
| Longitude | -74.33043 |
| Altitude | 35 m |
| Country | United States |