Distance from Columbus to San Angelo
Distance from Columbus to San Angelo is 1,833 kilometers. This air travel distance is equal to 1,139 miles.
The air travel (bird fly) shortest distance between Columbus and San Angelo is 1,833 km or 1,139 miles.
If you travel with an airplane (which has average speed of 560 miles) from Columbus to San Angelo, It takes 2.03 hours to arrive.
Columbus
Columbus is located in United States.
| GPS Coordinates (DMS) | 39° 57´ 40.2480'' N 82° 59´ 55.6440'' W |
|---|---|
| Latitude | 39.96118 |
| Longitude | -82.99879 |
| Altitude | 242 m |
| Country | United States |
Columbus Distances to Cities
| Columbus | Distance |
|---|---|
| Distance from Columbus Oh to San Francisco | 3,402 km |
| Distance from Columbus Oh to Sacramento | 3,300 km |
| Distance from Columbus Oh to Los Angeles | 3,183 km |
| Distance from Columbus Oh to Las Vegas | 2,836 km |
| Distance from Columbus Oh to Denver | 1,877 km |
San Angelo
San Angelo is located in United States.
| GPS Coordinates | 31° 27´ 49.5720'' N 100° 26´ 13.3440'' W |
|---|---|
| Latitude | 31.46377 |
| Longitude | -100.43704 |
| Altitude | 564 m |
| Country | United States |
San Angelo Distances to Cities
| San Angelo | Distance |
|---|---|
| Distance from San Angelo to Eagle | 1,948 km |
| Distance from San Angelo to West Odessa | 200 km |
| Distance from San Angelo to Moscow | 2,210 km |
| Distance from San Angelo to Twin Falls | 1,749 km |
| Distance from San Angelo to Albany Or | 2,455 km |