Distance from Columbia to San Angelo
Distance from Columbia to San Angelo is 1,837 kilometers. This air travel distance is equal to 1,141 miles.
The air travel (bird fly) shortest distance between Columbia and San Angelo is 1,837 km or 1,141 miles.
If you travel with an airplane (which has average speed of 560 miles) from Columbia to San Angelo, It takes 2.04 hours to arrive.
Columbia
Columbia is located in United States.
| GPS Coordinates (DMS) | 34° 0´ 2.5560'' N 81° 2´ 5.3160'' W |
|---|---|
| Latitude | 34.00071 |
| Longitude | -81.03481 |
| Altitude | 97 m |
| Country | United States |
Columbia Distances to Cities
| Columbia | Distance |
|---|---|
| Distance from Columbia Sc to San Francisco | 3,730 km |
| Distance from Columbia Sc to Helena Mt | 2,957 km |
| Distance from Columbia Sc to Richmond Va | 510 km |
| Distance from Columbia Sc to Houston | 1,433 km |
| Distance from Columbia Sc to Charleston Wv | 486 km |
San Angelo
San Angelo is located in United States.
| GPS Coordinates | 31° 27´ 49.5720'' N 100° 26´ 13.3440'' W |
|---|---|
| Latitude | 31.46377 |
| Longitude | -100.43704 |
| Altitude | 564 m |
| Country | United States |
San Angelo Distances to Cities
| San Angelo | Distance |
|---|---|
| Distance from San Angelo to Eagle | 1,948 km |
| Distance from San Angelo to West Odessa | 200 km |
| Distance from San Angelo to Moscow | 2,210 km |
| Distance from San Angelo to Twin Falls | 1,749 km |
| Distance from San Angelo to Albany Or | 2,455 km |