Distance from Christiansburg to Providence
Distance from Christiansburg to Providence is 932 kilometers. This air travel distance is equal to 579 miles.
The air travel (bird fly) shortest distance between Christiansburg and Providence is 932 km or 579 miles.
If you travel with an airplane (which has average speed of 560 miles) from Christiansburg to Providence, It takes 1.03 hours to arrive.
Christiansburg
Christiansburg is located in United States.
GPS Coordinates (DMS) | 37° 7´ 47.4600'' N 80° 24´ 32.1840'' W |
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Latitude | 37.12985 |
Longitude | -80.40894 |
Altitude | 637 m |
Country | United States |
Christiansburg Distances to Cities
Christiansburg | Distance |
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Distance from Christiansburg to Virginia Beach | 396 km |
Distance from Christiansburg to Los Angeles | 3,423 km |
Distance from Christiansburg to Roanoke | 44 km |
Distance from Christiansburg to Elko | 3,070 km |
Distance from Christiansburg to Tucson | 2,837 km |
Providence
Providence is located in United States.
GPS Coordinates | 41° 49´ 26.3640'' N 71° 24´ 46.1880'' W |
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Latitude | 41.82399 |
Longitude | -71.41283 |
Altitude | -17 m |
Country | United States |
Providence Distances to Cities
Providence | Distance |
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Distance from Providence to Boston | 66 km |
Distance from Providence to Smithfield | 16 km |
Distance from Providence to Phoenix | 3,671 km |
Distance from Providence to Virginia | 790 km |
Distance from Providence to Palmdale | 4,117 km |