Distance from Cebu City to Aleksandrovskoye
Distance from Cebu City to Aleksandrovskoye is 8,492 kilometers. This air travel distance is equal to 5,277 miles.
The air travel (bird fly) shortest distance between Cebu City and Aleksandrovskoye is 8,492 km= 5,277 miles.
If you travel with an airplane (which has average speed of 560 miles) from Cebu City to Aleksandrovskoye, It takes 9.42 hours to arrive.
Cebu City
Cebu City is located in Philippines.
| GPS Coordinates (DMS) | 10° 19´ 0.1920'' N 123° 53´ 26.5560'' E |
|---|---|
| Latitude | 10.31672 |
| Longitude | 123.89071 |
| Altitude | 37 m |
| Country | Philippines |
Cebu City Distances to Cities
| Cebu City | Distance |
|---|---|
| Distance from Cebu City to Solnechnogorsk | 8,870 km |
| Distance from Cebu City to Saint Petersburg | 9,219 km |
| Distance from Cebu City to Alapayevsk | 7,414 km |
| Distance from Cebu City to Katav Ivanovsk | 7,525 km |
| Distance from Cebu City to Aleksandrovskoye | 8,492 km |
Aleksandrovskoye
Aleksandrovskoye is located in Russia.
| GPS Coordinates | 44° 42´ 51.0120'' N 43° 0´ 2.9880'' E |
|---|---|
| Latitude | 44.71417 |
| Longitude | 43.00083 |
| Altitude | 295 m |
| Country | Russia |