Distance from Austin to Cleveland Heights
Distance from Austin to Cleveland Heights is 1,916 kilometers. This air travel distance is equal to 1,191 miles.
The air travel (bird fly) shortest distance between Austin and Cleveland Heights is 1,916 km or 1,191 miles.
If you travel with an airplane (which has average speed of 560 miles) from Austin to Cleveland Heights, It takes 2.13 hours to arrive.
Austin
Austin is located in United States.
| GPS Coordinates (DMS) | 30° 16´ 1.7400'' N 97° 44´ 35.0160'' W |
|---|---|
| Latitude | 30.26715 |
| Longitude | -97.74306 |
| Altitude | 165 m |
| Country | United States |
Austin Distances to Cities
| Austin | Distance |
|---|---|
| Distance from Austin Tx to San Francisco | 2,418 km |
| Distance from Austin Tx to Dallas | 293 km |
| Distance from Austin Tx to Santa Fe | 973 km |
| Distance from Austin Tx to Honolulu | 6,043 km |
| Distance from Austin Tx to Boston | 2,729 km |
Cleveland Heights
Cleveland Heights is located in United States.
| GPS Coordinates | 41° 31´ 12.1800'' N 81° 33´ 22.4640'' W |
|---|---|
| Latitude | 41.52005 |
| Longitude | -81.55624 |
| Altitude | 288 m |
| Country | United States |
Cleveland Heights Distances to Cities
| Cleveland Heights | Distance |
|---|---|
| Distance from Cleveland Heights to Lemont | 538 km |
| Distance from Cleveland Heights to Libertyville | 537 km |
| Distance from Cleveland Heights to Avon | 41 km |
| Distance from Cleveland Heights to Elmhurst | 533 km |
| Distance from Cleveland Heights to Redford | 173 km |