Distance from Arauca to Zipaquira
Distance from Arauca to Zipaquirá is 425 kilometers. This air travel distance is equal to 264 miles.
The air travel (bird fly) shortest distance between Arauca and Zipaquirá is 425 km= 264 miles.
If you travel with an airplane (which has average speed of 560 miles) from Arauca to Zipaquira, It takes 0.47 hours to arrive.
Arauca
Arauca is located in Colombia.
| GPS Coordinates (DMS) | 7° 4´ 45.7320'' N 70° 45´ 30.1680'' W |
|---|---|
| Latitude | 7.07937 |
| Longitude | -70.75838 |
| Altitude | 129 m |
| Country | Colombia |
Arauca Distances to Cities
| Arauca | Distance |
|---|---|
| Distance from Arauca to Tame | 127 km |
| Distance from Arauca to Bogota | 458 km |
| Distance from Arauca to Lorica | 606 km |
| Distance from Arauca to Antioquia | 506 km |
| Distance from Arauca to Barranquilla | 617 km |
Zipaquira
Zipaquira is located in Colombia.
| GPS Coordinates | 5° 1´ 19.4880'' N 74° 0´ 17.3160'' W |
|---|---|
| Latitude | 5.02208 |
| Longitude | -74.00481 |
| Altitude | 2607 m |
| Country | Colombia |
Zipaquirá Distances to Cities
| Zipaquirá | Distance |
|---|---|
| Distance from Zipaquira to Bogota | 46 km |
| Distance from Zipaquira to Agustindazzi | 561 km |
| Distance from Zipaquira to Girardot City | 120 km |
| Distance from Zipaquira to Quimbaya | 200 km |
| Distance from Zipaquira to Medellin | 220 km |