Distance from Arauca to Villanueva
Distance from Arauca to Villanueva is 239 kilometers. This air travel distance is equal to 149 miles.
The air travel (bird fly) shortest distance between Arauca and Villanueva is 239 km or 149 miles.
If you travel with an airplane (which has average speed of 560 miles) from Arauca to Villanueva, It takes 0.27 hours to arrive.
Arauca
Arauca is located in Colombia.
| GPS Coordinates (DMS) | 7° 4´ 45.7320'' N 70° 45´ 30.1680'' W |
|---|---|
| Latitude | 7.07937 |
| Longitude | -70.75838 |
| Altitude | 129 m |
| Country | Colombia |
Arauca Distances to Cities
| Arauca | Distance |
|---|---|
| Distance from Arauca to Tame | 127 km |
| Distance from Arauca to Bogota | 458 km |
| Distance from Arauca to Lorica | 606 km |
| Distance from Arauca to Antioquia | 506 km |
| Distance from Arauca to Barranquilla | 617 km |
Villanueva
Villanueva is located in Colombia.
| GPS Coordinates | 5° 16´ 59.9880'' N 71° 58´ 0.0120'' W |
|---|---|
| Latitude | 5.28333 |
| Longitude | -71.96667 |
| Altitude | 185 m |
| Country | Colombia |