Distance from Arauca to San Jose del Guaviare
Distance from Arauca to San José del Guaviare is 541 kilometers. This air travel distance is equal to 336 miles.
The air travel (bird fly) shortest distance between Arauca and San José del Guaviare is 541 km or 336 miles.
If you travel with an airplane (which has average speed of 560 miles) from Arauca to San Jose del Guaviare, It takes 0.6 hours to arrive.
Arauca
Arauca is located in Colombia.
| GPS Coordinates (DMS) | 7° 4´ 45.7320'' N 70° 45´ 30.1680'' W |
|---|---|
| Latitude | 7.07937 |
| Longitude | -70.75838 |
| Altitude | 129 m |
| Country | Colombia |
Arauca Distances to Cities
| Arauca | Distance |
|---|---|
| Distance from Arauca to Tame | 127 km |
| Distance from Arauca to Bogota | 458 km |
| Distance from Arauca to Lorica | 606 km |
| Distance from Arauca to Antioquia | 506 km |
| Distance from Arauca to Barranquilla | 617 km |
San Jose del Guaviare
San Jose del Guaviare is located in Colombia.
| GPS Coordinates | 2° 34´ 22.2960'' N 72° 38´ 45.2760'' W |
|---|---|
| Latitude | 2.57286 |
| Longitude | -72.64591 |
| Altitude | 184 m |
| Country | Colombia |
San José del Guaviare Distances to Cities
| San José del Guaviare | Distance |
|---|---|
| Distance from San Jose Del Guaviare to Villavicencio | 205 km |