Distance from Aleksandrow Lodzki to Senekal
Distance from Aleksandrów Łódzki to Senekal is 8,914 kilometers. This air travel distance is equal to 5,539 miles.
The air travel (bird fly) shortest distance between Aleksandrów Łódzki and Senekal is 8,914 km or 5,539 miles.
If you travel with an airplane (which has average speed of 560 miles) from Aleksandrow Lodzki to Senekal, It takes 9.89 hours to arrive.
Aleksandrow Lodzki
Aleksandrow Lodzki is located in Poland.
| GPS Coordinates (DMS) | 51° 49´ 10.7400'' N 19° 18´ 13.8240'' E |
|---|---|
| Latitude | 51.81965 |
| Longitude | 19.30384 |
| Altitude | 195 m |
| Country | Poland |
Aleksandrów Łódzki Distances to Cities
| Aleksandrów Łódzki | Distance |
|---|---|
| Distance from Aleksandrow Lodzki to Witbank | 8,661 km |
| Distance from Aleksandrow Lodzki to Saldanha | 9,398 km |
| Distance from Aleksandrow Lodzki to Lichtenburg | 8,663 km |
| Distance from Aleksandrow Lodzki to Durban | 9,120 km |
| Distance from Aleksandrow Lodzki to Senekal | 8,914 km |
Senekal
Senekal is located in South Africa.
| GPS Coordinates | 28° 19´ 10.9560'' S 27° 37´ 14.9520'' E |
|---|---|
| Latitude | -28.31971 |
| Longitude | 27.62082 |
| Altitude | 1431 m |
| Country | South Africa |