Distance from Albany to Wilkinsburg
Distance from Albany to Wilkinsburg is 567 kilometers. This air travel distance is equal to 352 miles.
The air travel (bird fly) shortest distance between Albany and Wilkinsburg is 567 km or 352 miles.
If you travel with an airplane (which has average speed of 560 miles) from Albany to Wilkinsburg, It takes 0.63 hours to arrive.
Albany
Albany is located in United States.
| GPS Coordinates (DMS) | 42° 39´ 9.2880'' N 73° 45´ 22.4280'' W |
|---|---|
| Latitude | 42.65258 |
| Longitude | -73.75623 |
| Altitude | 50 m |
| Country | United States |
Albany Distances to Cities
| Albany | Distance |
|---|---|
| Distance from Albany Ny to Las Vegas | 3,598 km |
| Distance from Albany Ny to Kingston | 83 km |
| Distance from Albany Ny to Sacramento | 4,011 km |
| Distance from Albany Ny to San Francisco | 4,120 km |
| Distance from Albany Ny to Los Angeles | 3,956 km |
Wilkinsburg
Wilkinsburg is located in United States.
| GPS Coordinates | 40° 26´ 30.2640'' N 79° 52´ 55.1640'' W |
|---|---|
| Latitude | 40.44174 |
| Longitude | -79.88199 |
| Altitude | 288 m |
| Country | United States |
Wilkinsburg Distances to Cities
| Wilkinsburg | Distance |
|---|---|
| Distance from Wilkinsburg to Santa Monica | 3,471 km |
| Distance from Wilkinsburg to San Diego | 3,417 km |
| Distance from Wilkinsburg to West Jordan | 2,701 km |
| Distance from Wilkinsburg to South Jordan | 2,701 km |
| Distance from Wilkinsburg to De Pere | 806 km |