Distance from Alabama to San Angelo
Distance from Alabama to San Angelo is 1,283 kilometers. This air travel distance is equal to 797 miles.
The air travel (bird fly) shortest distance between Alabama and San Angelo is 1,283 km or 797 miles.
If you travel with an airplane (which has average speed of 560 miles) from Alabama to San Angelo, It takes 1.42 hours to arrive.
Alabama
Alabama is located in United States.
| GPS Coordinates (DMS) | 32° 19´ 5.6280'' N 86° 54´ 8.2800'' W |
|---|---|
| Latitude | 32.31823 |
| Longitude | -86.90230 |
| Altitude | 65 m |
| Country | United States |
Alabama Distances to Cities
| Alabama | Distance |
|---|---|
| Distance from Alabama to California | 3,010 km |
| Distance from Alabama to New York | 1,481 km |
| Distance from Alabama to Atlanta | 283 km |
| Distance from Alabama to New Orleans | 400 km |
| Distance from Alabama to New Jersey | 1,412 km |
San Angelo
San Angelo is located in United States.
| GPS Coordinates | 31° 27´ 49.5720'' N 100° 26´ 13.3440'' W |
|---|---|
| Latitude | 31.46377 |
| Longitude | -100.43704 |
| Altitude | 564 m |
| Country | United States |
San Angelo Distances to Cities
| San Angelo | Distance |
|---|---|
| Distance from San Angelo to Eagle | 1,948 km |
| Distance from San Angelo to West Odessa | 200 km |
| Distance from San Angelo to Moscow | 2,210 km |
| Distance from San Angelo to Twin Falls | 1,749 km |
| Distance from San Angelo to Albany Or | 2,455 km |