Distance from Willimantic to Secaucus
Distance from Willimantic to Secaucus is 186 kilometers. This air travel distance is equal to 116 miles.
The air travel (bird fly) shortest distance between Willimantic and Secaucus is 186 km or 116 miles.
If you travel with an airplane (which has average speed of 560 miles) from Willimantic to Secaucus, It takes 0.21 hours to arrive.
Willimantic
Willimantic is located in United States.
| GPS Coordinates (DMS) | 41° 42´ 38.3400'' N 72° 12´ 29.2680'' W |
|---|---|
| Latitude | 41.71065 |
| Longitude | -72.20813 |
| Altitude | 67 m |
| Country | United States |
Willimantic Distances to Cities
Secaucus
Secaucus is located in United States.
| GPS Coordinates | 40° 47´ 22.3800'' N 74° 3´ 23.5080'' W |
|---|---|
| Latitude | 40.78955 |
| Longitude | -74.05653 |
| Altitude | 2 m |
| Country | United States |