Distance from Willimantic to Sayreville Junction
Distance from Willimantic to Sayreville Junction is 226 kilometers. This air travel distance is equal to 140 miles.
The air travel (bird fly) shortest distance between Willimantic and Sayreville Junction is 226 km or 140 miles.
If you travel with an airplane (which has average speed of 560 miles) from Willimantic to Sayreville Junction, It takes 0.25 hours to arrive.
Willimantic
Willimantic is located in United States.
| GPS Coordinates (DMS) | 41° 42´ 38.3400'' N 72° 12´ 29.2680'' W |
|---|---|
| Latitude | 41.71065 |
| Longitude | -72.20813 |
| Altitude | 67 m |
| Country | United States |
Willimantic Distances to Cities
Sayreville Junction
Sayreville Junction is located in United States.
| GPS Coordinates | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
|---|---|
| Latitude | 40.46538 |
| Longitude | -74.33043 |
| Altitude | 35 m |
| Country | United States |