Distance from Sandusky to Westerville
Distance from Sandusky to Westerville is 148 kilometers. This air travel distance is equal to 92 miles.
The air travel (bird fly) shortest distance between Sandusky and Westerville is 148 km or 92 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sandusky to Westerville, It takes 0.16 hours to arrive.
Sandusky
Sandusky is located in United States.
GPS Coordinates (DMS) | 41° 26´ 56.1840'' N 82° 42´ 28.6560'' W |
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Latitude | 41.44894 |
Longitude | -82.70796 |
Altitude | 183 m |
Country | United States |
Sandusky Distances to Cities
Sandusky | Distance |
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Distance from Sandusky to South Euclid | 100 km |
Distance from Sandusky to Waukesha | 488 km |
Distance from Sandusky to Pittsburgh | 254 km |
Distance from Sandusky to Tucson | 2,702 km |
Distance from Sandusky to Janesville | 540 km |
Westerville
Westerville is located in United States.
GPS Coordinates | 40° 7´ 34.2120'' N 82° 55´ 44.6520'' W |
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Latitude | 40.12617 |
Longitude | -82.92907 |
Altitude | 262 m |
Country | United States |
Westerville Distances to Cities
Westerville | Distance |
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Distance from Westerville to Newark Ca | 3,381 km |
Distance from Westerville to Waukesha | 546 km |
Distance from Westerville to Wauwatosa | 533 km |
Distance from Westerville to Howard | 649 km |
Distance from Westerville to Muskego | 533 km |