Distance from Secaucus to West Warwick
Distance from Secaucus to West Warwick is 235 kilometers. This air travel distance is equal to 146 miles.
The air travel (bird fly) shortest distance between Secaucus and West Warwick is 235 km or 146 miles.
If you travel with an airplane (which has average speed of 560 miles) from Secaucus to West Warwick, It takes 0.26 hours to arrive.
Secaucus
Secaucus is located in United States.
| GPS Coordinates (DMS) | 40° 47´ 22.3800'' N 74° 3´ 23.5080'' W |
|---|---|
| Latitude | 40.78955 |
| Longitude | -74.05653 |
| Altitude | 2 m |
| Country | United States |
Secaucus Distances to Cities
West Warwick
West Warwick is located in United States.
| GPS Coordinates | 41° 41´ 48.8040'' N 71° 31´ 18.9840'' W |
|---|---|
| Latitude | 41.69689 |
| Longitude | -71.52194 |
| Altitude | 18 m |
| Country | United States |
West Warwick Distances to Cities
| West Warwick | Distance |
|---|---|
| Distance from West Warwick to Woonsocket | 34 km |
| Distance from West Warwick to Centralia | 4,074 km |
| Distance from West Warwick to Cheshire | 117 km |
| Distance from West Warwick to Inglewood | 4,159 km |
| Distance from West Warwick to Kennewick | 3,797 km |