Distance from Secaucus to West Mifflin
Distance from Secaucus to West Mifflin is 494 kilometers. This air travel distance is equal to 307 miles.
The air travel (bird fly) shortest distance between Secaucus and West Mifflin is 494 km or 307 miles.
If you travel with an airplane (which has average speed of 560 miles) from Secaucus to West Mifflin, It takes 0.55 hours to arrive.
Secaucus
Secaucus is located in United States.
| GPS Coordinates (DMS) | 40° 47´ 22.3800'' N 74° 3´ 23.5080'' W |
|---|---|
| Latitude | 40.78955 |
| Longitude | -74.05653 |
| Altitude | 2 m |
| Country | United States |
Secaucus Distances to Cities
West Mifflin
West Mifflin is located in United States.
| GPS Coordinates | 40° 21´ 48.2400'' N 79° 51´ 59.1840'' W |
|---|---|
| Latitude | 40.36340 |
| Longitude | -79.86644 |
| Altitude | 333 m |
| Country | United States |
West Mifflin Distances to Cities
| West Mifflin | Distance |
|---|---|
| Distance from West Mifflin to Menasha | 826 km |
| Distance from West Mifflin to Centralia | 3,508 km |
| Distance from West Mifflin to Cheshire | 600 km |
| Distance from West Mifflin to Phoenix | 2,953 km |
| Distance from West Mifflin to Weirton | 62 km |