Distance from Austintown to Weirton Heights
Distance from Austintown to Weirton Heights is 79 kilometers. This air travel distance is equal to 49 miles.
The air travel (bird fly) shortest distance between Austintown and Weirton Heights is 79 km or 49 miles.
If you travel with an airplane (which has average speed of 560 miles) from Austintown to Weirton Heights, It takes 0.09 hours to arrive.
Austintown
Austintown is located in United States.
| GPS Coordinates (DMS) | 41° 6´ 6.1920'' N 80° 45´ 52.2720'' W |
|---|---|
| Latitude | 41.10172 |
| Longitude | -80.76452 |
| Altitude | 345 m |
| Country | United States |
Austintown Distances to Cities
Weirton Heights
Weirton Heights is located in United States.
| GPS Coordinates | 40° 24´ 30.2400'' N 80° 32´ 21.2640'' W |
|---|---|
| Latitude | 40.40840 |
| Longitude | -80.53924 |
| Altitude | 365 m |
| Country | United States |
Weirton Heights Distances to Cities
| Weirton Heights | Distance |
|---|---|
| Distance from Weirton Heights to South Hill | 3,399 km |
| Distance from Weirton Heights to Valinda | 3,368 km |
| Distance from Weirton Heights to Bridgewater | 500 km |
| Distance from Weirton Heights to Centralia | 3,454 km |
| Distance from Weirton Heights to Phoenix | 2,897 km |