Distance from Cedar Hill to Watauga
Distance from Cedar Hill to Watauga is 41 kilometers. This air travel distance is equal to 25 miles.
The air travel (bird fly) shortest distance between Cedar Hill and Watauga is 41 km or 25 miles.
If you travel with an airplane (which has average speed of 560 miles) from Cedar Hill to Watauga, It takes 0.05 hours to arrive.
Cedar Hill
Cedar Hill is located in United States.
GPS Coordinates (DMS) | 32° 35´ 18.4920'' N 96° 57´ 22.0320'' W |
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Latitude | 32.58847 |
Longitude | -96.95612 |
Altitude | 258 m |
Country | United States |
Cedar Hill Distances to Cities
Watauga
Watauga is located in United States.
GPS Coordinates | 32° 51´ 28.4760'' N 97° 15´ 17.0640'' W |
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Latitude | 32.85791 |
Longitude | -97.25474 |
Altitude | 188 m |
Country | United States |
Watauga Distances to Cities
Watauga | Distance |
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Distance from Watauga to Plum | 1,775 km |
Distance from Watauga to Weatherford | 52 km |
Distance from Watauga to Parker | 1,000 km |
Distance from Watauga to Hobbs | 551 km |
Distance from Watauga to Amarillo | 497 km |