Distance from Wallingford to Sayreville Junction
Distance from Wallingford to Sayreville Junction is 168 kilometers. This air travel distance is equal to 104 miles.
The air travel (bird fly) shortest distance between Wallingford and Sayreville Junction is 168 km or 104 miles.
If you travel with an airplane (which has average speed of 560 miles) from Wallingford to Sayreville Junction, It takes 0.19 hours to arrive.
Wallingford
Wallingford is located in United States.
| GPS Coordinates (DMS) | 41° 27´ 25.3440'' N 72° 49´ 23.3760'' W |
|---|---|
| Latitude | 41.45704 |
| Longitude | -72.82316 |
| Altitude | 23 m |
| Country | United States |
Wallingford Distances to Cities
| Wallingford | Distance |
|---|---|
| Distance from Wallingford to Boston | 177 km |
| Distance from Wallingford to Cambridge | 175 km |
| Distance from Wallingford to Bridgeport | 45 km |
| Distance from Wallingford to Norristown | 259 km |
| Distance from Wallingford to Selden | 68 km |
Sayreville Junction
Sayreville Junction is located in United States.
| GPS Coordinates | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
|---|---|
| Latitude | 40.46538 |
| Longitude | -74.33043 |
| Altitude | 35 m |
| Country | United States |