Distance from Viterbo to San Vito dei Normanni
Distance from Viterbo to San Vito dei Normanni is 506 kilometers. This air travel distance is equal to 314 miles.
The air travel (bird fly) shortest distance between Viterbo and San Vito dei Normanni is 506 km or 314 miles.
If you travel with an airplane (which has average speed of 560 miles) from Viterbo to San Vito dei Normanni, It takes 0.56 hours to arrive.
Viterbo
Viterbo is located in Italy.
| GPS Coordinates (DMS) | 42° 25´ 23.5920'' N 12° 6´ 41.0760'' E |
|---|---|
| Latitude | 42.42322 |
| Longitude | 12.11141 |
| Altitude | 358 m |
| Country | Italy |
Viterbo Distances to Cities
| Viterbo | Distance |
|---|---|
| Distance from Viterbo to Rome | 68 km |
| Distance from Viterbo to Perugia | 80 km |
| Distance from Viterbo to Venice | 335 km |
| Distance from Viterbo to Florence | 166 km |
| Distance from Viterbo to Pompei | 273 km |
San Vito dei Normanni
San Vito dei Normanni is located in Italy.
| GPS Coordinates | 40° 39´ 23.1120'' N 17° 42´ 29.3040'' E |
|---|---|
| Latitude | 40.65642 |
| Longitude | 17.70814 |
| Altitude | 111 m |
| Country | Italy |