Distance from Villa Park to Sandusky
Distance from Villa Park to Sandusky is 442 kilometers. This air travel distance is equal to 275 miles.
The air travel (bird fly) shortest distance between Villa Park and Sandusky is 442 km or 275 miles.
If you travel with an airplane (which has average speed of 560 miles) from Villa Park to Sandusky, It takes 0.49 hours to arrive.
Villa Park
Villa Park is located in United States.
| GPS Coordinates (DMS) | 41° 53´ 23.1000'' N 87° 59´ 20.2200'' W |
|---|---|
| Latitude | 41.88975 |
| Longitude | -87.98895 |
| Altitude | 215 m |
| Country | United States |
Villa Park Distances to Cities
| Villa Park | Distance |
|---|---|
| Distance from Villa Park to Faribault | 506 km |
| Distance from Villa Park to Northfield | 508 km |
| Distance from Villa Park to Eagan | 530 km |
| Distance from Villa Park to East Lansing | 304 km |
| Distance from Villa Park to Sacramento | 2,856 km |
Sandusky
Sandusky is located in United States.
| GPS Coordinates | 41° 26´ 56.1840'' N 82° 42´ 28.6560'' W |
|---|---|
| Latitude | 41.44894 |
| Longitude | -82.70796 |
| Altitude | 183 m |
| Country | United States |
Sandusky Distances to Cities
| Sandusky | Distance |
|---|---|
| Distance from Sandusky to South Euclid | 100 km |
| Distance from Sandusky to Waukesha | 488 km |
| Distance from Sandusky to Pittsburgh | 254 km |
| Distance from Sandusky to Tucson | 2,702 km |
| Distance from Sandusky to Janesville | 540 km |