Distance from U.S. Virgin Islands to Sandy Springs
Distance from U.S. Virgin Islands to Sandy Springs is 2,594 kilometers. This air travel distance is equal to 1,612 miles.
The air travel (bird fly) shortest distance between U.S. Virgin Islands and Sandy Springs is 2,594 km or 1,612 miles.
If you travel with an airplane (which has average speed of 560 miles) from U.S. Virgin Islands to Sandy Springs, It takes 2.88 hours to arrive.
U.S. Virgin Islands
| GPS Coordinates (DMS) | 18° 20´ 8.7720'' N 64° 53´ 46.7880'' W |
|---|---|
| Latitude | 18.33577 |
| Longitude | -64.89633 |
| Altitude | 61 m |
| Country | U.S. Virgin Islands |
U.S. Virgin Islands Distances to Countries
| U.S. Virgin Islands | Distance |
|---|---|
| Distance from New Caledonia to U.S. Virgin Islands | 14,738 km |
| Distance from Austria to U.S. Virgin Islands | 7,733 km |
| Distance from Montenegro to U.S. Virgin Islands | 8,180 km |
Sandy Springs
Sandy Springs is located in United States.
| GPS Coordinates | 33° 55´ 27.3720'' N 84° 22´ 42.7440'' W |
|---|---|
| Latitude | 33.92427 |
| Longitude | -84.37854 |
| Altitude | 333 m |
| Country | United States |