Distance from Trumbull to Sayreville Junction
Distance from Trumbull to Sayreville Junction is 129 kilometers. This air travel distance is equal to 80 miles.
The air travel (bird fly) shortest distance between Trumbull and Sayreville Junction is 129 km or 80 miles.
If you travel with an airplane (which has average speed of 560 miles) from Trumbull to Sayreville Junction, It takes 0.14 hours to arrive.
Trumbull
Trumbull is located in United States.
| GPS Coordinates (DMS) | 41° 14´ 34.3320'' N 73° 12´ 2.4120'' W |
|---|---|
| Latitude | 41.24287 |
| Longitude | -73.20067 |
| Altitude | 75 m |
| Country | United States |
Trumbull Distances to Cities
| Trumbull | Distance |
|---|---|
| Distance from Trumbull to Boston | 217 km |
| Distance from Trumbull to Westport | 17 km |
| Distance from Trumbull to Port Chester | 47 km |
| Distance from Trumbull to Ansonia | 15 km |
| Distance from Trumbull to Braintree | 213 km |
Sayreville Junction
Sayreville Junction is located in United States.
| GPS Coordinates | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
|---|---|
| Latitude | 40.46538 |
| Longitude | -74.33043 |
| Altitude | 35 m |
| Country | United States |