Distance from Tewksbury to Sayville
Distance from Tewksbury to Sayville is 259 kilometers. This air travel distance is equal to 161 miles.
The air travel (bird fly) shortest distance between Tewksbury and Sayville is 259 km or 161 miles.
If you travel with an airplane (which has average speed of 560 miles) from Tewksbury to Sayville, It takes 0.29 hours to arrive.
Tewksbury
Tewksbury is located in United States.
| GPS Coordinates (DMS) | 42° 36´ 38.3400'' N 71° 14´ 3.1920'' W |
|---|---|
| Latitude | 42.61065 |
| Longitude | -71.23422 |
| Altitude | 40 m |
| Country | United States |
Tewksbury Distances to Cities
| Tewksbury | Distance |
|---|---|
| Distance from Tewksbury to Portsmouth Nh | 64 km |
| Distance from Tewksbury to Bedford Nh | 44 km |
| Distance from Tewksbury to West New York | 307 km |
| Distance from Tewksbury to Lincoln Ne | 2,118 km |
| Distance from Tewksbury to Aberdeen Wa | 4,110 km |
Sayville
Sayville is located in United States.
| GPS Coordinates | 40° 44´ 9.3480'' N 73° 4´ 55.4160'' W |
|---|---|
| Latitude | 40.73593 |
| Longitude | -73.08206 |
| Altitude | 9 m |
| Country | United States |