Distance from Tewksbury to East Patchogue
Distance from Tewksbury to East Patchogue is 252 kilometers. This air travel distance is equal to 157 miles.
The air travel (bird fly) shortest distance between Tewksbury and East Patchogue is 252 km or 157 miles.
If you travel with an airplane (which has average speed of 560 miles) from Tewksbury to East Patchogue, It takes 0.28 hours to arrive.
Tewksbury
Tewksbury is located in United States.
| GPS Coordinates (DMS) | 42° 36´ 38.3400'' N 71° 14´ 3.1920'' W |
|---|---|
| Latitude | 42.61065 |
| Longitude | -71.23422 |
| Altitude | 40 m |
| Country | United States |
Tewksbury Distances to Cities
| Tewksbury | Distance |
|---|---|
| Distance from Tewksbury to Portsmouth Nh | 64 km |
| Distance from Tewksbury to Bedford Nh | 44 km |
| Distance from Tewksbury to West New York | 307 km |
| Distance from Tewksbury to Lincoln Ne | 2,118 km |
| Distance from Tewksbury to Aberdeen Wa | 4,110 km |
East Patchogue
East Patchogue is located in United States.
| GPS Coordinates | 40° 46´ 1.3440'' N 72° 59´ 46.3920'' W |
|---|---|
| Latitude | 40.76704 |
| Longitude | -72.99622 |
| Altitude | 9 m |
| Country | United States |