Distance between São Sebastião do Caí and Teutônia
Distance between São Sebastião do Caí and Teutônia is 45.4 km. This distance is equal to 28.21 miles, and 24.5 nautical miles.
The distance line on map shows distance from São Sebastião do Caí to Teutônia between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between São Sebastião do Caí to Teutônia,
It takes 0.05 hours to arrive.
| São Sebastião do Caí | -29.5875726 | -51.3735594 |
|---|---|---|
| Teutônia | -29.4468976 | -51.8140104 |
| Distance | 45.4 km | 28.21 miles |
Related Distances
- Distance between São Sebastião do Caí and Itaqui (503,94 km.)
- Distance between São Sebastião do Caí and Guaporé (96,31 km.)
- Distance between Júlio de Castilhos and São Sebastião do Caí (227,38 km.)
- Distance between São Sebastião do Caí and Lagoa Vermelha (153,81 km.)
- Distance between São Sebastião do Caí and Três de Maio (346,43 km.)
- Distance between Nova Prata and São Sebastião do Caí (92,47 km.)