Distance from Faribault to Sioux Falls
Distance from Faribault to Sioux Falls is 288 kilometers. This air travel distance is equal to 179 miles.
The air travel (bird fly) shortest distance between Faribault and Sioux Falls is 288 km or 179 miles.
If you travel with an airplane (which has average speed of 560 miles) from Faribault to Sioux Falls, It takes 0.32 hours to arrive.
Faribault
Faribault is located in United States.
| GPS Coordinates (DMS) | 44° 17´ 41.8560'' N 93° 16´ 7.7880'' W |
|---|---|
| Latitude | 44.29496 |
| Longitude | -93.26883 |
| Altitude | 304 m |
| Country | United States |
Faribault Distances to Cities
Sioux Falls
Sioux Falls is located in United States.
| GPS Coordinates | 43° 32´ 59.8920'' N 96° 42´ 1.1880'' W |
|---|---|
| Latitude | 43.54997 |
| Longitude | -96.70033 |
| Altitude | 449 m |
| Country | United States |
Sioux Falls Distances to Cities
| Sioux Falls | Distance |
|---|---|
| Distance from Sioux Falls to Rapid City | 529 km |
| Distance from Sioux Falls to La Crosse | 441 km |
| Distance from Sioux Falls to Onalaska | 442 km |
| Distance from Sioux Falls to Sheboygan | 725 km |
| Distance from Sioux Falls to Wausau | 586 km |