Distance from Shenandoah to Warrensburg
Distance from Shenandoah to Warrensburg is 961 kilometers. This air travel distance is equal to 597 miles.
The air travel (bird fly) shortest distance between Shenandoah and Warrensburg is 961 km or 597 miles.
If you travel with an airplane (which has average speed of 560 miles) from Shenandoah to Warrensburg, It takes 1.07 hours to arrive.
Shenandoah
Shenandoah is located in United States.
| GPS Coordinates (DMS) | 30° 24´ 4.6800'' N 91° 0´ 3.3840'' W |
|---|---|
| Latitude | 30.40130 |
| Longitude | -91.00094 |
| Altitude | 14 m |
| Country | United States |
Shenandoah Distances to Cities
| Shenandoah | Distance |
|---|---|
| Distance from Shenandoah to Omaha | 1,284 km |
| Distance from Shenandoah to Nashville | 750 km |
| Distance from Shenandoah to Cedar Rapids | 1,289 km |
| Distance from Shenandoah to Oklahoma City | 828 km |
| Distance from Shenandoah to Lancaster Ca | 2,585 km |
Warrensburg
Warrensburg is located in United States.
| GPS Coordinates | 38° 45´ 46.0440'' N 93° 44´ 9.7800'' W |
|---|---|
| Latitude | 38.76279 |
| Longitude | -93.73605 |
| Altitude | 270 m |
| Country | United States |
Warrensburg Distances to Cities
| Warrensburg | Distance |
|---|---|
| Distance from Warrensburg to Dallas | 719 km |
| Distance from Warrensburg to Virginia Beach | 1,576 km |
| Distance from Warrensburg to Iowa City | 373 km |
| Distance from Warrensburg to Los Angeles | 2,252 km |
| Distance from Warrensburg to West Lafayette | 615 km |