Distance from Montgomery Village to Severna Park
Distance from Montgomery Village to Severna Park is 57 kilometers. This air travel distance is equal to 35 miles.
The air travel (bird fly) shortest distance between Montgomery Village and Severna Park is 57 km or 35 miles.
If you travel with an airplane (which has average speed of 560 miles) from Montgomery Village to Severna Park, It takes 0.06 hours to arrive.
Montgomery Village
Montgomery Village is located in United States.
| GPS Coordinates (DMS) | 39° 10´ 36.3720'' N 77° 11´ 42.9360'' W |
|---|---|
| Latitude | 39.17677 |
| Longitude | -77.19526 |
| Altitude | 118 m |
| Country | United States |
Montgomery Village Distances to Cities
Severna Park
Severna Park is located in United States.
| GPS Coordinates | 39° 4´ 13.4040'' N 76° 32´ 42.8640'' W |
|---|---|
| Latitude | 39.07039 |
| Longitude | -76.54524 |
| Altitude | 14 m |
| Country | United States |