Distance from Severn to Sayreville Junction
Distance from Severn to Sayreville Junction is 251 kilometers. This air travel distance is equal to 156 miles.
The air travel (bird fly) shortest distance between Severn and Sayreville Junction is 251 km or 156 miles.
If you travel with an airplane (which has average speed of 560 miles) from Severn to Sayreville Junction, It takes 0.28 hours to arrive.
Severn
Severn is located in United States.
GPS Coordinates (DMS) | 39° 8´ 13.3800'' N 76° 41´ 53.8800'' W |
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Latitude | 39.13705 |
Longitude | -76.69830 |
Altitude | 49 m |
Country | United States |
Severn Distances to Cities
Severn | Distance |
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Distance from Severn to Hudson | 466 km |
Distance from Severn to Lorton | 66 km |
Distance from Severn to Linden | 267 km |
Distance from Severn to Berea | 504 km |
Distance from Severn to Mount Vernon Ny | 314 km |
Sayreville Junction
Sayreville Junction is located in United States.
GPS Coordinates | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
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Latitude | 40.46538 |
Longitude | -74.33043 |
Altitude | 35 m |
Country | United States |